0=-16x^2-10x+100

Solution for 0=-16x^2-10x+100 equation:

0=-16x^2-10x+100

We move all terms to the left:

0-(-16x^2-10x+100)=0

We add all the numbers together, and all the variables

-(-16x^2-10x+100)=0

We get rid of parentheses

16x^2+10x-100=0

a = 16; b = 10; c = -100;
Δ = b2-4ac
Δ = 102-4·16·(-100)
Δ = 6500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6500}=\sqrt{100*65}=\sqrt{100}*\sqrt{65}=10\sqrt{65}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10\sqrt{65}}{2*16}=\frac{-10-10\sqrt{65}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10\sqrt{65}}{2*16}=\frac{-10+10\sqrt{65}}{32}
$